2(2v)^2=0

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Solution for 2(2v)^2=0 equation: 



2(2v)^2=0

a = 22; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·22·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{44}=0$

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